UPSKILL MATH PLUS

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Factorise by using the identity \(a^2 - b^2 = (a + b)(a - b)\).
 
(i) \(a^2 - 1 =\)
 
(ii) \(9k^2 - 25 =\)
 
(iii) \(64x^2 - 81y^2 =\)
Answer variants:
\((a + 1)\) and \((a + 1)\)
\(8x - 9y\) and \(8x - 9y\)
\((a - 1)\) and \((a - 1)\)
\(3k^2 - 5\) and \(3k - 5\)
\(8x + 9y\) and \(8x - 9y\)
\(3k + 5\) and \(3k + 5\)
\(3k + 5\) and \(3k - 5\)
\((a + 1)\) and \((a - 1)\)
\(8x + 9y\) and \(8x + 9y\)