UPSKILL MATH PLUS

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1. Subtract \(-3ab - 8\) from \(3ab + 8\). Also, subtract \(3ab + 8\) from \(-3ab - 8\).
 
Answer:
 
\(-3ab - 8\) from \(3ab + 8 =\)
 
\(3ab + 8\) from \(-3ab - 8 =\)
 
2. Add: \(2a + b + 3c\) and \(a + \frac{1}{3}b + \frac{2}{5}c\)
 
Answer:
 
Solution \(=\) ia+iib+iic