UPSKILL MATH PLUS

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Let \(A = \{x \in \mathbb{W}|x < 2\}\), \(B = \{x \in \mathbb{N}|1 < x \leq 4\}\) and \(C = \{3,5\}\). Then verify that \((A \cup B) \times C = (A \times C) \cup (B \times C)\).
 
Answer:
 
To prove:
 
\((A \cup B) \times C = (A \times C) \cup (B \times C)\)
 
Explanation:
 
\(A \cup B =\) \(\{\)​​\(\}\)
 
\((A \cup B) \times C =\) \(\{\)​​\(\}\)
 
\(A \times C = \{\)\(\}\)
 
\(B \times C = \{\)\(\}\)
 
\((A \times C) \cup (B \times C) = \{\)\(\}\)
 
\((A \cup B) \times C = (A \times C) \cup (B \times C)\)
 
Hence, we proved.
 
[Note: Enter the first and the second coordinates of the ordered pairs in the increasing order.]