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Let \(A =\) The set of all natural numbers less than \(8\), \(B =\) The set of all prime numbers less than \(8\), \(C =\) The set of even prime numbers. Verify that \(A \times (B - C) = (A \times B) - (A \times C)\)
 
Answer:
 
To prove:
 
\(A \times (B - C) = (A \times B) - (A \times C)\)
 
Explanation:
 
\(B - C =\) i,i,i
 
\(A \times (B - C) = \{\)\(\}\)
 
\(A \times B = \{\)\(\}\)
 
\(A \times C =\{\)\(\}\)
 
 
\((A \times B) - (A \times C) =\{\)\(\}\)
 
Therefore, \(A \times (B - C) = (A \times B) - (A \times C)\)
 
Hence, we proved.
 
[Note: Enter the first and the second coordinates of the ordered pairs in the increasing order.]